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  4. The vertical extension in a light spring by a weight of 1 kg suspended from the wire is 9.8 cm. The period of oscillation is :

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Q. The vertical extension in a light spring by a weight of 1 kg suspended from the wire is 9.8 cm. The period of oscillation is :

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Solution:

Time period of oscillation $ T=2\pi \sqrt{\frac{\Delta l}{g}} $ $ =2\pi \sqrt{\frac{9.8\times {{10}^{-2}}}{9.8}}=\frac{2\pi }{10}\sec $