The velocity v versus time t graph of a body in a straight line is as shown in figure. The displacement of the body in five seconds is

Question

The velocity v versus time t graph of a body in a straight line is as shown in figure. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/79940fdca9324b9f136a0b6fbfd83afd-.png" /> The displacement of the body in five seconds is (A) 2 m (B) 3 m (C) 4 m (D) 5 m

Tardigrade Admin · Accepted Answer

Displacement is the algebraic sum of area under velocity-time graph. ∴ Displacement in 5 s =(1/2) × 2 × 2+(1/2) × 1 × 2-(1/2) × 2 × 1+1 × 1=3 m

Q. The velocity $v$ versus time $t$ graph of a body in a straight line is as shown in figure.

The displacement of the body in five seconds is

2 m

3 m

4 m

5 m

Displacement is the algebraic sum of area under velocity-time graph.
$∴$ Displacement in $5 s$
$= \frac{1}{2} \times 2 \times 2 + \frac{1}{2} \times 1 \times 2 - \frac{1}{2} \times 2 \times 1 + 1 \times 1 = 3 m$

Q. The velocity v versus time t graph of a body in a straight line is as shown in figure. The displacement of the body in five seconds is

2 m

3 m

4 m

5 m

Displacement is the algebraic sum of area under velocity-time graph. ∴ Displacement in 5s =21​×2×2+21​×1×2−21​×2×1+1×1=3m

Q. The velocity $v$ versus time $t$ graph of a body in a straight line is as shown in figure.

The displacement of the body in five seconds is

Displacement is the algebraic sum of area under velocity-time graph.
$∴$ Displacement in $5 s$
$= \frac{1}{2} \times 2 \times 2 + \frac{1}{2} \times 1 \times 2 - \frac{1}{2} \times 2 \times 1 + 1 \times 1 = 3 m$