Question

The velocity-time graph of a linear motion is shown in figure. The distance from the starting point after $8$ sec is ______ m

Answer 1

Answer: 5

Distance from the starting point is equal to displacement.
Displacement = area of $v-t$ graph
$=\frac{1}{2}[4+2]4-\frac{1}{2}[4+3]\times 2$
$=5m$
Note: Here distance travelled is not asked, but the distance from the starting point