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  4. The velocity-time graph of a linear motion is shown in figure. The distance from the starting point after 8 sec is m

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Q. The velocity-time graph of a linear motion is shown in figure. The distance from the starting point after $8$ sec is ______ mPhysics Question Image

Motion in a Straight Line

Solution:

Distance from the starting point is equal to displacement.
Displacement = area of $v-t$ graph
$ = \frac{1}{2} [ 4 + 2]4 - \frac{1}{2}[4 + 3]\times 2$
$ = 5\,m$
Note: Here distance travelled is not asked, but the distance from the starting point