The velocity of electron in second shell of hydrogen atom is:

Question

The velocity of electron in second shell of hydrogen atom is: (A) 10.94 × 106 m / sec (B) 18.88 × 106 m / sec (C) 1.88 × 106 m / sec (D) 1.094 × 106 m / sec

Tardigrade Admin · Accepted Answer

According to Bohr, velocity of an electron (v) =2.188 × 106 ( Z / n ) m / sec for H ; Z =1 n =2 (given) ∴ V=(2.188 × 106 × 1/2)=1.094 × 106 m / sec

Q. The velocity of electron in second shell of hydrogen atom is:

$10.94 \times 1 0^{6} m / sec$

$18.88 \times 1 0^{6} m / sec$

$1.88 \times 1 0^{6} m / sec$

$1.094 \times 1 0^{6} m / sec$

According to Bohr, velocity of an electron (v)

$= 2.188 \times 1 0^{6} \frac{Z}{n} m / sec$

for $H; Z = 1 n = 2$ (given)

$∴ V = \frac{2.188 \times 1 0 ^{6} \times 1}{2} = 1.094 \times 1 0^{6} m / sec$

Q. The velocity of electron in second shell of hydrogen atom is:

10.94×106m/sec

18.88×106m/sec

1.88×106m/sec

1.094×106m/sec

According to Bohr, velocity of an electron (v) =2.188×106nZ​m/sec for H;Z=1n=2 (given) ∴V=22.188×106×1​=1.094×106m/sec

$10.94 \times 1 0^{6} m / sec$

$18.88 \times 1 0^{6} m / sec$

$1.88 \times 1 0^{6} m / sec$

$1.094 \times 1 0^{6} m / sec$

According to Bohr, velocity of an electron (v)

$= 2.188 \times 1 0^{6} \frac{Z}{n} m / sec$

for $H; Z = 1 n = 2$ (given)

$∴ V = \frac{2.188 \times 1 0 ^{6} \times 1}{2} = 1.094 \times 1 0^{6} m / sec$