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Q. The velocity of electron in second shell of hydrogen atom is:

Structure of Atom

Solution:

According to Bohr, velocity of an electron (v)

$=2.188 \times 10^{6} \frac{ Z }{ n } m / sec$

for $H ; Z =1 \quad n =2$ (given)

$\therefore V=\frac{2.188 \times 10^{6} \times 1}{2}=1.094 \times 10^{6} m / sec$