The velocity of a body moving with uniform acceleration at a given instant of time t is 10 m/s. After 5 s its velocity is 20 m/s. Distance travelled in that time is:

Question

The velocity of a body moving with uniform acceleration at a given instant of time t is 10 m/s. After 5 s its velocity is 20 m/s. Distance travelled in that time is: (A) 300 m (B) 400 m (C) 150 m (D) 75 m

Tardigrade Admin · Accepted Answer

From equation of motion v=u+a t Given, v=20 m / s , u=10 m / s , t=5 s ∴ a=(10/5)=2 m / s2 Also, v2=u2+2 a s(20)2 =(10)2+2 × 2 s ⇒ s=(300/4)=75 m

Q. The velocity of a body moving with uniform acceleration at a given instant of time t is $10 m / s$ . After $5 s$ its velocity is $20 m / s$ . Distance travelled in that time is:

300 m

400 m

150 m

75 m

From equation of motion $v = u + a t$
Given, $v = 20 m / s, u = 10 m / s, t = 5 s$
$∴ a = \frac{10}{5} = 2 m / s^{2}$
Also, $v^{2} = u^{2} + 2 a s (20)^{2}$
$= (10)^{2} + 2 \times 2 s$
$\Rightarrow s = \frac{300}{4} = 75 m$

Q. The velocity of a body moving with uniform acceleration at a given instant of time t is 10m/s. After 5s its velocity is 20m/s. Distance travelled in that time is: