The variation of velocity of a particle moving along a straight line is shown in figure. The distance travelled by the particle in 12 s is

Question

The variation of velocity of a particle moving along a straight line is shown in figure. The distance travelled by the particle in 12 s is (A) 37.5 m (B) 32.5 m (C) 35.0 m (D) None of these

Tardigrade Admin · Accepted Answer

Area from 0 to 10 s =(1/2)[10+4] 5=35 m Area from 10 to 12 s =(1/2) × 2 ×(-2.5)=-2.5 m Distance travelled =35+2.5=37.5 m

Q. The variation of velocity of a particle moving along a straight line is shown in figure. The distance travelled by the particle in $12 s$ is

37.5 m

32.5 m

35.0 m

None of these

Area from $0$ to $10 s = \frac{1}{2} [10 + 4] 5 = 35 m$
Area from $10$ to $12 s = \frac{1}{2} \times 2 \times (- 2.5) = - 2.5 m$
Distance travelled $= 35 + 2.5 = 37.5 m$

Q. The variation of velocity of a particle moving along a straight line is shown in figure. The distance travelled by the particle in 12s is