Thank you for reporting, we will resolve it shortly
Q.
The variation of velocity of a particle moving along a straight line is shown in figure. The distance travelled by the particle in $12\, s$ is
Motion in a Straight Line
Solution:
Area from $0$ to $10\, s =\frac{1}{2}[10+4] 5=35\, m$
Area from $10$ to $12\, s =\frac{1}{2} \times 2 \times(-2.5)=-2.5\, m$
Distance travelled $=35+2.5=37.5\, m$
