Question

The variance of the data $2,4,6,8,10$ is

• A. $6$
• B. $7$
• C. $8$
• D. None of these

Answer 1

Answer: (C)

Here,$\bar{x}=\frac{2+4+6+8+10}{5}=6$
Hence, variance$=\frac{1}{n}\Sigma {\left(x_i-\bar{x}\right)}^2$
$=\frac{1}{5}\left\{{\left(2-6\right)}^2+{\left(4-6\right)}^2+\left(6-6\right)+{\left(8-6\right)}^2+{\left(10-6\right)}^2\right\}$
$=\frac{1}{5}\left\{(16+4+0+4+16\right\}=\frac{1}{5}\left\{40\right\}=8$