The vapour pressure of pure water at 75°C is 296 torr the vapour pressure lowering due to 0.1 m solute is

Question

The vapour pressure of pure water at 75°C is 296 torr the vapour pressure lowering due to 0.1 m solute is (A) 0.533 torr (B) 0.296 torr (C) 0.333 torr (D) 0.428 torr

Tardigrade Admin · Accepted Answer

(Δ P/296)=(0.1/0.1+(1000)18) where (1000'/18) = no. of moles water ∴ Δ P=0.533 torr

Q. The vapour pressure of pure water at $7 5^{\circ} C$ is $296$ torr the vapour pressure lowering due to $0.1 m$ solute is

0.533 torr

0.296 torr

0.333 torr

0.428 torr

$\frac{Δ P}{296} = \frac{0.1}{0.1 + \frac{1000}{18}}$
where $\frac{100 0 ^{'}}{18}$ = no. of moles water
$∴ Δ P = 0.533$ torr

Q. The vapour pressure of pure water at 75∘C is 296 torr the vapour pressure lowering due to 0.1m solute is