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  4. The vapour pressure of pure water at 75°C is 296 torr the vapour pressure lowering due to 0.1 m solute is

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Q. The vapour pressure of pure water at $75^{\circ}C$ is $296$ torr the vapour pressure lowering due to $0.1\, m$ solute is

Solutions

Solution:

$\frac{\Delta P}{296}=\frac{0.1}{0.1+\frac{1000}{18}}$
where $\frac{1000'}{18}$ = no. of moles water
$\therefore \Delta P=0.533$ torr