The vapour density of a mixture containing NO2 and N2O4 is 38.3 at 27°C. What will be the mole of NO2 in 100 mole mixture.

Question

The vapour density of a mixture containing NO2 and N2O4 is 38.3 at 27°C. What will be the mole of NO2 in 100 mole mixture. (A) 76.6 mol (B) 33.48 mol (C) 50 mol (D) 46 mol

Tardigrade Admin · Accepted Answer

Given, Vapour density of mixture NO2 and N2O4 = 38.3 Temperature = 27Â°C Moles of NO2 + 2NO2 mixture = 100 3(NO2)=100 NO2=(100/3)=33.4 mol

Q. The vapour density of a mixture containing $NO X_{2}$ and $N X_{2} O X_{4}$ is 38.3 at $27 X^{\circ} C$ . What will be the mole of $NO X_{2}$ in 100 mole mixture.

76.6 mol

33.48 mol

50 mol

46 mol

Given,
Vapour density of mixture $N O_{2}$ and $N_{2} O_{4} = 38.3$
Temperature $= 2 7^{°} C$
Moles of $N O_{2} + 2 N O_{2}$ mixture $= 100$
$3 (N O_{2}) = 100$
$N O_{2} = \frac{100}{3} = 33.4$ mol

Q. The vapour density of a mixture containing NOX2​ and NX2​OX4​ is 38.3 at 27X∘C. What will be the mole of NOX2​ in 100 mole mixture.