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  4. The vapour density of a mixture containing NO2 and N2O4 is 38.3 at 27°C. What will be the mole of NO2 in 100 mole mixture.

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Q. The vapour density of a mixture containing $\ce{NO2}$ and $\ce{N2O4}$ is 38.3 at $\ce{27^{\circ}C}$. What will be the mole of $\ce{NO_2}$ in 100 mole mixture.

UPSEEUPSEE 2019

Solution:

Given,
Vapour density of mixture $NO_2$ and $N_2O_4 = 38.3$
Temperature $= 27^°C$
Moles of $NO_2 + 2NO_2$ mixture $= 100$
$3(NO_2)=100$
$NO_{2}=\frac{100}{3}=33.4$ mol