The values of the Henry’s law constant of Ar,CO2,CH4 and O2 in water at 25° C are 40.30 , 1.67, 0.41 and 34.86 kbar, respectively. The order of their solubility in water at the same temperature and pressure is

Question

The values of the Henry’s law constant of Ar,CO2,CH4 and O2 in water at 25° C are 40.30 , 1.67, 0.41 and 34.86 kbar, respectively. The order of their solubility in water at the same temperature and pressure is (A) Ar > O2 > CO2 > CH4 (B) CH4> CO2> Ar> O2 (C)  CH4> CO2>O2 > Ar (D)  Ar> CH4> O2> CO2

Tardigrade Admin · Accepted Answer

By Henryâs law, p textgas propto X textgas (in liquid solution) and p textgas =KH × chi textgas KH = Henryâs law constant. ∴ At a given partial pressure of gas, KH propto(1/ chi textgas) ∴ The greater the value ofKH the less its solubility. Here, KH of Ar > O2 > CO2 > CH4 ∴ Solubility of CH4 > CO2 > O2 > Ar.

Q. The values of the Henry’s law constant of $A r, C O_{2}, C H_{4}$ and $O_{2}$ in water at $2 5^{\circ} C$ are $40.30$ , $1.67, 0.41$ and $34.86 kba r$ , respectively. The order of their solubility in water at the same temperature and pressure is

$A r > O_{2} > C O_{2} > C H_{4}$

$C H_{4} > C O_{2} > A r > O_{2}$

$C H_{4} > C O_{2} > O_{2} > A r$

$A r > C H_{4} > O_{2} > C O_{2}$

Q. The values of the Henry’s law constant of Ar,CO2​,CH4​ and O2​ in water at 25∘C are 40.30 , 1.67,0.41 and 34.86kbar, respectively. The order of their solubility in water at the same temperature and pressure is

Ar>O2​>CO2​>CH4​

CH4​>CO2​>Ar>O2​

CH4​>CO2​>O2​>Ar

Ar>CH4​>O2​>CO2​

Q. The values of the Henry’s law constant of $A r, C O_{2}, C H_{4}$ and $O_{2}$ in water at $2 5^{\circ} C$ are $40.30$ , $1.67, 0.41$ and $34.86 kba r$ , respectively. The order of their solubility in water at the same temperature and pressure is

$A r > O_{2} > C O_{2} > C H_{4}$

$C H_{4} > C O_{2} > A r > O_{2}$

$C H_{4} > C O_{2} > O_{2} > A r$

$A r > C H_{4} > O_{2} > C O_{2}$