1. Tardigrade
  2. Question
  3. Chemistry
  4. The values of the Henry’s law constant of Ar,CO2,CH4 and O2 in water at 25° C are 40.30 , 1.67, 0.41 and 34.86 kbar, respectively. The order of their solubility in water at the same temperature and pressure is

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Q. The values of the Henry’s law constant of $Ar,CO_2,CH_4$ and $O_2$ in water at $25^\circ C$ are $40.30$ , $1.67, 0.41$ and $34.86\, kbar$, respectively. The order of their solubility in water at the same temperature and pressure is

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Solution:

By Henry’s law,
${p}_{\text{gas}} \propto X_{\text{gas}}$ (in liquid solution)
and $p_{\text{gas}} =K_{H} \times \chi_{\text{gas}}$
$K_{H}$ = Henry’s law constant.
$\therefore $ At a given partial pressure of gas,
$K_{H } \propto\frac{1}{\chi_{\text{gas}}}$
$\therefore $ The greater the value of$K_H$ the less its solubility.
Here, $K_H$ of $Ar > O_2 > CO_2 > CH_4$
$\therefore $ Solubility of$ CH_4 > CO_2 > O_2 > Ar$.