Question

The value of universal gas constant is $R=8.3J/k-mol$. The value of $R$ in atmosphere litre per kelvin per mol

• A. 8.12
• B. 0.00812
• C. 81.2
• D. 0.0812

Answer 1

Answer: (D)

As, $R=8.3J/K$ -mol
Now, $n_1{u}_1=n_2{u}_2$
$(u_1$ and $u_2$ are units while $n_1$ and $n_2$ are the numerical values)
$\therefore n_2=\frac{n_1{u}_1}{u_2}$
$=\frac{8.3J/K-mol}{atmL/K-mol}$
$=\frac{8.3J/K-mol}{\left(1.013\times 10^{5}N/m^2\right)\left(10^{-3}{m}^3\right)/K-mol}$
$=\frac{8.12}{10^2}=0.0812$
$\therefore 8.3J/K-mol=0.0812atmL/K$ -mol