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Tardigrade
Question
Mathematics
The value of the expression sec 610° operatornamecosec 160°- cot 380° tan 470° is equal to
Q. The value of the expression
sec
61
0
∘
cosec
16
0
∘
−
cot
38
0
∘
tan
47
0
∘
is equal to
80
103
Application of Derivatives
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A
cos
−
1
(
cos
(
−
1
))
B
cot
(
cot
−
1
(
−
1
)
)
C
The gradient of the tangent to the curve
x
y
=
1
at its point with abscissa 1 .
D
The greatest integer satisfying the inequality
3
2
x
+
1
−
2
3
x
−
1
>
1
.
Solution:
sec
(
72
0
∘
−
11
0
∘
)
cosec
(
18
0
∘
−
2
0
∘
)
−
cot
(
36
0
∘
+
2
0
∘
)
tan
(
36
0
∘
+
11
0
∘
)
=
c
o
s
11
0
∘
1
⋅
s
i
n
2
0
∘
1
−
cot
2
0
∘
tan
11
0
∘
=
s
i
n
2
2
0
∘
−
1
+
cot
2
2
0
∘
=
−
[
cosec
2
2
0
∘
−
cot
2
2
0
∘
]
=
−
1
Now verify B, C, D