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Mathematics
The value of the expression sec 610° operatornamecosec 160°- cot 380° tan 470° is equal to
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Q. The value of the expression $\sec 610^{\circ} \operatorname{cosec} 160^{\circ}-\cot 380^{\circ} \tan 470^{\circ}$ is equal to
Application of Derivatives
A
$\cos ^{-1}(\cos (-1))$
B
$\cot \left(\cot ^{-1}(-1)\right)$
C
The gradient of the tangent to the curve $x y=1$ at its point with abscissa 1 .
D
The greatest integer satisfying the inequality $\frac{2 x+1}{3}-\frac{3 x-1}{2}>1$.
Solution:
$\sec \left(720^{\circ}-110^{\circ}\right) \operatorname{cosec}\left(180^{\circ}-20^{\circ}\right)-\cot \left(360^{\circ}+20^{\circ}\right) \tan \left(360^{\circ}+110^{\circ}\right)$
$=\frac{1}{\cos 110^{\circ}} \cdot \frac{1}{\sin 20^{\circ}}-\cot 20^{\circ} \tan 110^{\circ} $
$=\frac{-1}{\sin ^2 20^{\circ}}+\cot ^2 20^{\circ}=-\left[\operatorname{cosec}^2 20^{\circ}-\cot ^2 20^{\circ}\right]=-1$
$\text { Now verify B, C, D }$