Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The value of the determinant |x x+1 x-1 x| is
Q. The value of the determinant
∣
∣
x
x
−
1
x
+
1
x
∣
∣
is
477
179
Determinants
Report Error
A
1
46%
B
−
1
33%
C
2
8%
D
0
13%
Solution:
We have,
∣
∣
x
x
−
1
x
+
1
x
∣
∣
=
x
(
x
)
−
(
x
+
1
)
(
x
−
1
)
=
x
2
−
(
x
2
−
1
)
=
x
2
−
x
2
+
1
=
1