1. Tardigrade
  2. Question
  3. Mathematics
  4. The value of the determinant |x x+1 x-1 x| is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The value of the determinant $\begin{vmatrix}x & x+1 \\ x-1 & x\end{vmatrix}$ is

Determinants

Solution:

We have, $\begin{vmatrix}x & x+1 \\ x-1 & x\end{vmatrix}=x(x)-(x+1)(x-1)$
$=x^2-\left(x^2-1\right)$
$=x^2-x^2+1=1$