Question

The value of ${\tan }^{-1}\frac{1}{\sqrt{2}}-{\tan }^{-1}\frac{\sqrt{5-2\sqrt{6}}}{1+\sqrt{6}}$ is equal

• A. $\frac{\pi }{6}$
• B. $\frac{\pi }{4}$
• C. $\frac{\pi }{3}$
• D. $\frac{\pi }{8}$

Answer 1

Answer: (A)

${\tan }^{-1}\frac{1}{\sqrt{2}}-\left({\tan }^{-1}\sqrt{3}-{\tan }^{-1}\sqrt{2}\right)=\frac{\pi }{6}$