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Q. The value of $\tan ^{-1} \frac{1}{\sqrt{2}}-\tan ^{-1} \frac{\sqrt{5-2 \sqrt{6}}}{1+\sqrt{6}}$ is equal

Inverse Trigonometric Functions

Solution:

$\tan ^{-1} \frac{1}{\sqrt{2}}-\left(\tan ^{-1} \sqrt{3}-\tan ^{-1} \sqrt{2}\right)=\frac{\pi}{6}$