Question

The value of $\sin \theta$ in terms of $\tan \theta$ is

• A. $\frac{\tan \theta }{\sqrt{1-{\tan }^2\theta }}$
• B. $\frac{{\tan }^2\theta }{\sqrt{1+{\tan }^2\theta }}$
• C. $\frac{{\tan }^2\theta }{\sqrt{1-{\tan }^2\theta }}$
• D. $\frac{\tan \theta }{\sqrt{1+{\tan }^2\theta }}$

Answer 1

Answer: (D)

Use ${\sec }^2\theta -{\tan }^2\theta =1$.