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Mathematics
The value of sin θ in terms of tan θ is
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Q. The value of $\sin \theta$ in terms of $\tan \theta$ is
Trigonometry
A
$\frac{\tan \theta}{\sqrt{1-\tan ^2 \theta}}$
B
$\frac{\tan ^2 \theta}{\sqrt{1+\tan ^2 \theta}}$
C
$\frac{\tan ^2 \theta}{\sqrt{1-\tan ^2 \theta}}$
D
$\frac{\tan \theta}{\sqrt{1+\tan ^2 \theta}}$
Solution:
Use $\sec ^2 \theta-\tan ^2 \theta=1$.