Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The value of sin 50°- sin 70°+ sin 10° is equal to
Q. The value of
sin
5
0
∘
−
sin
7
0
∘
+
sin
1
0
∘
is equal to
1798
191
Report Error
A
1
B
0
C
2
1
D
2
Solution:
sin
5
0
∘
+
sin
1
0
∘
−
sin
7
0
∘
2
sin
3
0
∘
cos
2
0
∘
−
sin
7
0
∘
2.
2
1
⋅
cos
2
0
∘
−
sin
7
0
∘
cos
2
0
∘
−
cos
(
9
0
∘
−
7
0
∘
)
=
0