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  4. The value of sin 50°- sin 70°+ sin 10° is equal to

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Q. The value of $\sin 50^{\circ}-\sin 70^{\circ}+\sin 10^{\circ}$ is equal to

Solution:

$\sin 50^{\circ}+\sin 10^{\circ}-\sin 70^{\circ}$
$2 \sin 30^{\circ} \cos 20^{\circ}-\sin 70^{\circ}$
$\not 2 . \frac{1}{\not 2} \cdot \cos 20^{\circ}-\sin 70^{\circ}$
$\cos 20^{\circ}-\cos \left(90^{\circ}-70^{\circ}\right)=0$