Q. The value of $sin^{2} 5 1^{\circ} + sin^{2} 3 9^{\circ}$ is

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A

1

23%

B

0

27%

C

$sin 1 2^{\circ}$

33%

D

$cos 1 2^{\circ}$

17%

Solution:

$sin^{2} 5 1^{\circ} + sin^{2} 3 9^{\circ}$
$= cos^{2} 3 9^{\circ} + sin^{2} 3 9^{\circ}$
$= 1$