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Q. The value of $\sin^2 51^\circ + \sin^2 39^\circ$ is

KCETKCET 2020

Solution:

$\sin ^{2} 51^{\circ}+\sin ^{2} 39^{\circ}$
$=\cos ^{2} 39^{\circ}+\sin ^{2} 39^{\circ}$
$=1$