The value of horizontal component of earths magnetic field at a place is 0.35×10-4 tesla. If the angle of dip is 600, the value of vertical component of earths magnetic field is about :

Question

The value of horizontal component of earths magnetic field at a place is 0.35×10-4 tesla. If the angle of dip is 600, the value of vertical component of earths magnetic field is about : (A) 0.10×10-4 T (B) 0.2×10-4 T (C) 0.4×10-4 T (D) 0.6×10-4 T

Tardigrade Admin · Accepted Answer

By = Bh tan θ = 0.35 × 10-4 × tan 60 = 0.60 × 10-1 T.

Q. The value of horizontal component of earths magnetic field at a place is $0.35 \times 1 0^{- 4}$ tesla. If the angle of dip is $6 0^{0}$ , the value of vertical component of earths magnetic field is about :

$0.10 \times 1 0^{- 4} T$

$0.2 \times 1 0^{- 4} T$

$0.4 \times 1 0^{- 4} T$

$0.6 \times 1 0^{- 4} T$

$B_{y} = B_{h}$ tan $θ$ = $0.35 \times 1 0^{- 4} \times$ tan 60 = $0.60 \times 1 0^{- 1}$ T.

Q. The value of horizontal component of earths magnetic field at a place is 0.35×10−4 tesla. If the angle of dip is 600, the value of vertical component of earths magnetic field is about :

0.10×10−4T

0.2×10−4T

0.4×10−4T

0.6×10−4T