Question

The value of horizontal component of earths magnetic field at a place is $0.35\times10^{-4}$ tesla. If the angle of dip is $60^0$, the value of vertical component of earths magnetic field is about :

• A. $0.10\times10^{-4}\,T$
• B. $0.2\times10^{-4}\,T$
• C. $0.4\times10^{-4}\,T$
• D. $0.6\times10^{-4}\,T$

Answer 1

Answer: (D)

$B_y = B_h$ tan $\theta$ = $0.35 \times 10^{-4} \times$ tan 60 = $0.60 \times 10^{-1}$ T.