The value of gravitational acceleration âgâ at a height âhâ above the earthâs surface is (g/4) then (R = radius of earth)

Question

The value of gravitational acceleration âgâ at a height âhâ above the earthâs surface is (g/4) then (R = radius of earth) (A) h = R (B) h = (R/2) (C) h = (R/3) (D) h = (R/4)

Tardigrade Admin · Accepted Answer

Value of gravitational acceleration at a height h above th earth's surface is given by g prime=g((R/R+h))2 ∴ ( g /4)= g (( R / R + h ))2 Or (R/R+h)=(1/2) Or h + R =2 R Longrightarrow h = R

Q. The value of gravitational acceleration ‘ $g$ ’ at a height ‘ $h$ ’ above the earth’s surface is $\frac{g}{4}$ then ( $R =$ radius of earth)

$h = R$

$h = \frac{R}{2}$

$h = \frac{R}{3}$

$h = \frac{R}{4}$

Value of gravitational acceleration at a height $h$ above th earth's surface is given by $g^{'} = g (\frac{R}{R + h})^{2}$ $∴ \frac{g}{4} = g (\frac{R}{R + h})^{2}$
Or $\frac{R}{R + h} = \frac{1}{2}$
Or $h + R = 2 R$
$⟹ h = R$

Q. The value of gravitational acceleration ‘g’ at a height ‘h’ above the earth’s surface is 4g​ then (R= radius of earth)

h=R

h=2R​

h=3R​

h=4R​