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Q. The value of gravitational acceleration ‘$g$’ at a height ‘$h$’ above the earth’s surface is $\frac{g}{4}$ then ($R =$ radius of earth)

MHT CETMHT CET 2016Gravitation

Solution:

Value of gravitational acceleration at a height $h$ above th earth's surface is given by $g^{\prime}=g\left(\frac{R}{R+h}\right)^{2}$ $\therefore \frac{ g }{4}= g \left(\frac{ R }{ R + h }\right)^{2}$
Or $\frac{R}{R+h}=\frac{1}{2}$
Or $h + R =2 R$
$\Longrightarrow h = R$