The value of g on earth's surface is 980 cms-2. The value at a height of 64 km from surface of earth is

Question

The value of g on earth's surface is 980 cms-2. The value at a height of 64 km from surface of earth is (A) 960.4 cm s-2 (B) 984.9 cm s-2 (C) 982.45 cm s-2 (D) 977.55 cm s-2

Tardigrade Admin · Accepted Answer

Using gh = g (R2/(R + h)2), we get gh = 980 ((6400/6400 + 64) )2 = 960 cm s-2

Q. The value of g on earth's surface is $980 c m s^{- 2}$ . The value at a height of 64 km from surface of earth is

$960.4 c m s^{- 2}$

$984.9 c m s^{- 2}$

$982.45 c m s^{- 2}$

$977.55 c m s^{- 2}$

Using $g_{h} = g \frac{R ^{2}}{( R + h ) ^{2}}$ , we get $g_{h} = 980 (\frac{6400}{6400 + 64})^{2}$ = 960 cm $s^{- 2}$

Q. The value of g on earth's surface is 980cms−2. The value at a height of 64 km from surface of earth is

960.4cms−2

984.9cms−2

982.45cms−2

977.55cms−2