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  4. The value of g on earth's surface is 980 cms-2. The value at a height of 64 km from surface of earth is

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Q. The value of g on earth's surface is $980\,cms^{-2}$. The value at a height of 64 km from surface of earth is

Gravitation

Solution:

Using $g_h = g \frac{R^2}{(R + h)^2}$, we get $g_h = 980 \left(\frac{6400}{6400 + 64} \right)^2$ = 960 cm $s^{-2}$