The value of cot ((-15 π/4)) is

Question

The value of cot ((-15 π/4)) is (A) (-1/√3) (B) 1 (C) √3 (D) -√3

Tardigrade Admin · Accepted Answer

cot (-(15 π/4))= - cot ((15 π/4)) [∵ cot (-θ)=- cot θ] = - cot (4 π-(π/4))=- cot (2 π × 2-(π/4)) =-(- cot (π/4))= cot (π/4)=1 [∵ cot (2 n π-θ)=- cot θ]

Q. The value of $cot (\frac{- 15 π}{4})$ is

$\frac{- 1}{3}$

1

$3$

$- 3$

$cot (- \frac{15 π}{4}) = - cot (\frac{15 π}{4}) [∵ cot (- θ) = - cot θ]$
$= - cot (4 π - \frac{π}{4}) = - cot (2 π \times 2 - \frac{π}{4})$
$= - (- cot \frac{π}{4}) = cot \frac{π}{4} = 1$
$[∵ cot (2 nπ - θ) = - cot θ]$

Q. The value of cot(4−15π​) is

3​−1​

1

3​

−3​

cot(−415π​)=−cot(415π​)[∵cot(−θ)=−cotθ] =−cot(4π−4π​)=−cot(2π×2−4π​) =−(−cot4π​)=cot4π​=1 [∵cot(2nπ−θ)=−cotθ]

Q. The value of $cot (\frac{- 15 π}{4})$ is

$\frac{- 1}{3}$

$3$

$- 3$

$cot (- \frac{15 π}{4}) = - cot (\frac{15 π}{4}) [∵ cot (- θ) = - cot θ]$
$= - cot (4 π - \frac{π}{4}) = - cot (2 π \times 2 - \frac{π}{4})$
$= - (- cot \frac{π}{4}) = cot \frac{π}{4} = 1$
$[∵ cot (2 nπ - θ) = - cot θ]$