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Q. The value of $\cot \left(\frac{-15 \pi}{4}\right)$ is

Trigonometric Functions

Solution:

$ \cot \left(-\frac{15 \pi}{4}\right)= -\cot \left(\frac{15 \pi}{4}\right) [\because \cot (-\theta)=-\cot \theta]$
$= -\cot \left(4 \pi-\frac{\pi}{4}\right)=-\cot \left(2 \pi \times 2-\frac{\pi}{4}\right) $
$=-\left(-\cot \frac{\pi}{4}\right)=\cot \frac{\pi}{4}=1 $
$ {[\because \cot (2 n \pi-\theta)=-\cot \theta] }$