Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The value of cos 2 45°- sin 2 15° is
Q. The value of
cos
2
4
5
∘
−
sin
2
1
5
∘
is
1659
210
Report Error
A
2
3
B
4
3
C
2
2
3
+
1
D
2
2
3
−
1
Solution:
cos
2
4
5
∘
−
sin
2
1
5
∘
=
4
3
( OR )
cos
2
4
5
∘
−
sin
2
1
5
∘
=
cos
(
4
5
∘
+
1
5
∘
)
cos
(
4
5
∘
−
1
5
∘
)
=
4
3