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  4. The value of cos 2 45°- sin 2 15° is

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Q. The value of $\cos ^{2} 45^{\circ}-\sin ^{2} 15^{\circ}$ is

Solution:

$\cos ^{2} 45^{\circ}-\sin ^{2} 15^{\circ}=\frac{\sqrt{3}}{4}$
( OR )
$\cos ^{2} 45^{\circ}-\sin ^{2} 15^{\circ}=\cos \left(45^{\circ}+15^{\circ}\right) \cos \left(45^{\circ}-15^{\circ}\right)$
$=\frac{\sqrt{3}}{4}$