Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The value of cos 1200°+ tan 1485° is
Q. The value of
cos
120
0
∘
+
tan
148
5
∘
is
10491
201
KCET
KCET 2021
Trigonometric Functions
Report Error
A
2
1
23%
B
2
3
35%
C
−
2
3
29%
D
−
2
1
13%
Solution:
cos
(
3
×
36
0
∘
+
12
0
∘
)
+
tan
(
4
×
36
0
∘
+
4
5
∘
)
=
2
1