1. Tardigrade
  2. Question
  3. Mathematics
  4. The value of cos 1200°+ tan 1485° is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The value of $\cos 1200^{\circ}+\tan 1485^{\circ}$ is

KCETKCET 2021Trigonometric Functions

Solution:

$\cos \left(3 \times 360^{\circ}+120^{\circ}\right)+\tan \left(4 \times 360^{\circ}+45^{\circ}\right)$
$=\frac{1}{2}$