Question

The value of antilog ${}_5\left({\log }_2\left(\sqrt{\text{ anti }{\log }_2\left({\log }_{2}16\right)}\right)\right)$ is

• A. 32
• B. 4
• C. 25
• D. 5

Answer 1

Answer: (C)

${\log }_{2}16=4\therefore$ anti ${\log }_2\left({\log }_{2}16\right)=16$
$\therefore$ anti ${\log }_5\left({\log }_{2}4\right)$ anti ${\log }_{5}2=5^2=25$.