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  4. The value of antilog 5( log 2(√ text anti log 2( log 2 16))) is

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Q. The value of antilog ${ }_5\left(\log _2\left(\sqrt{\text { anti } \log _2\left(\log _2 16\right)}\right)\right)$ is

Continuity and Differentiability

Solution:

$ \log _2 16=4 \therefore$ anti $\log _2\left(\log _2 16\right)=16$
$\therefore$ anti $\log _5\left(\log _2 4\right)$ anti $\log _5 2=5^2=25$.