Q. The value of amp $(iω) +$ amp $(i ω^{2})$ is

2312 250 Rajasthan PETRajasthan PET 2010 Report Error

A

$0$

B

$\frac{π}{6}$

C

$\frac{π}{2}$

D

$π$

Solution:

amp $(iω) +$ amp $(i ω^{2})$
= amp $(i^{2} ω^{3})$
= amp $(- 1)$
$= π$