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Q. The value of amp $ (i\omega )+ $ amp $ (i{{\omega }^{2}}) $ is

Rajasthan PETRajasthan PET 2010

Solution:

amp $ (i\omega )+ $ amp $ (i{{\omega }^{2}}) $
= amp $ ({{i}^{2}}{{\omega }^{3}}) $
= amp $ (-1) $
$ =\pi $