Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The value of (98)2 is
Q. The value of
(
98
)
2
is ___
72
144
Indices
Report Error
Answer:
9604
Solution:
We have,
(
98
)
2
=
(
100
−
2
)
2
Since,
(
a
−
b
)
2
=
(
a
2
−
2
ab
+
b
2
)
=
(
100
)
2
−
2
×
100
×
2
+
(
2
)
2
=
10000
−
400
+
4
=
9604