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Q. The value of $(98)^2$ is ___

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Solution:

We have, $(98)^2=(100-2)^2$
Since, $(a-b)^2=\left(a^2-2 a b+b^2\right)$
$ =(100)^2-2 \times 100 \times 2+(2)^2 $
$ =10000-400+4=9604$