The V- shape of SO2 is due to the presence of

Question

The V- shape of SO2 is due to the presence of (A) two σ and one π-bonds (B) two σ and two π-bonds (C) two σ bond and one l.p. of electron (D) twoσ bond and two π-bonds and one l.p. of electron

Tardigrade Admin · Accepted Answer

SO2. Total valence e- = 6× 3 = 18 = 8 × 2 + 2 No. of hybridised orbital = (8 × 2/8) + (2/2) = 3

Q. The $V$ - shape of $S O_{2}$ is due to the presence of

two $σ$ and one $π$ -bonds

two $σ$ and two $π$ -bonds

two $σ$ bond and one l.p. of electron

two $σ$ bond and two $π$ -bonds and one l.p. of electron

$S O_{2}$ . Total valence $e^{-} = 6 \times 3 = 18$
$= 8 \times 2 + 2$
No. of hybridised orbital $= \frac{8 \times 2}{8} + \frac{2}{2} = 3$

Q. The V- shape of SO2​ is due to the presence of

two σ and one π-bonds

two σ and two π-bonds

two σ bond and one l.p. of electron

twoσ bond and two π-bonds and one l.p. of electron