Question

The $V$- shape of $SO_2$ is due to the presence of

• A. two $\sigma$ and one $\pi$-bonds
• B. two $\sigma$ and two $\pi$-bonds
• C. two $\sigma$ bond and one l.p. of electron
• D. two$\sigma$ bond and two $\pi$-bonds and one l.p. of electron

Answer 1

Answer: (D)

$SO_2$. Total valence $e^- = 6\times 3 = 18$
$= 8 \times 2 + 2$
No. of hybridised orbital $ = \frac{8 \times 2}{8} + \frac{2}{2} = 3$