The unpaired electron in Ni(CO)4 is

Question

The unpaired electron in Ni(CO)4 is (A) 1 (B) 2 (C) 3 (D) 0

Tardigrade Admin · Accepted Answer

In N i(C O)4, there is no unpaired electron. It is diamagnetic. Oxidation state of N i in [N i(C O)4] complex compound is zero. N i=3 d8 4 s2 s p3 hybridised orbitals of Ni [N i(C O)4]

Q. The unpaired electron in $N i (CO)_{4}$ is

1

2

3

0

In $N i (CO)_{4}$ , there is no unpaired electron.
It is diamagnetic.
Oxidation state of $N i$ in $[N i (CO)_{4}]$
complex compound is zero.
$N i = 3 d^{8} 4 s^{2}$
$s p^{3}$ hybridised orbitals of $N i$
$[N i (CO)_{4}]$

Q. The unpaired electron in Ni(CO)4​ is

1

2

3

0

In Ni(CO)4​, there is no unpaired electron. It is diamagnetic. Oxidation state of Ni in [Ni(CO)4​] complex compound is zero. Ni=3d84s2 sp3 hybridised orbitals of Ni [Ni(CO)4​]

Q. The unpaired electron in $N i (CO)_{4}$ is

In $N i (CO)_{4}$ , there is no unpaired electron.
It is diamagnetic.
Oxidation state of $N i$ in $[N i (CO)_{4}]$
complex compound is zero.
$N i = 3 d^{8} 4 s^{2}$
$s p^{3}$ hybridised orbitals of $N i$
$[N i (CO)_{4}]$